Problem ByteLandian Gold Coins

Bytelandian gold coins[Java Program]

In Byteland they have a very strange monetary system.

Each Bytelandian gold coin has an integer number written on it. A coin n
can be exchanged in a bank into three coins: n/2, n/3 and n/4.
But these numbers are all rounded down (the banks have to make a profit).

You can also sell Bytelandian coins for American dollars. The exchange
rate is 1:1. But you can not buy Bytelandian coins.

You have one gold coin. What is the maximum amount of American dollars
you can get for it?

Input

The input will contain several test cases (not more than 10). Each
testcase is a single line with a number n, 0 <= n <= 1 000 000 000.
It is the number written on your coin.

Output

For each test case output a single line, containing the maximum amount
of American dollars you can make.

Example

Input:
12
2

Output:
13
2

You can change 12 into 6, 4 and 3, and then change these into
$6+$4+$3 = $13.

If you try changing the coin 2 into 3 smaller coins, you will get
1, 0 and 0, and later you can get no more than $1 out of them.
It is better just to change the 2 coin directly into $2.

Program:-

/**

 * @(#)ByteLG.java

 *

 *

 * @author Suyash Bhalla

 * @version 1.00 2014/12/31

 */

import java.io.*;

import java.util.HashMap;

class ByteLG {

static HashMap<Long,Long> hm=new HashMap<Long,Long>();

    public static void main(String ar[])throws IOException{

    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

    String st;

    while((st=br.readLine())!=null){

    long t=Long.parseLong(st);

    t=meth(t);

    System.out.println(t);

    }

    }    

    public static long meth(long n){

    if(n<12){

    return n;

    }else if(hm.containsKey(n)){

    return hm.get(n);

    }else{

    long t=meth(n/2)+meth(n/3)+meth(n/4);

    hm.put(n,t);

    return t;

    }

    }

}

-------------------X-------------------X-------------------X-------------------X-------------------X-------------------X------------